2x+8=4/12x=20

Solution for 2x+8=4/12x=20 equation:

2x+8=4/12x=20

We move all terms to the left:

2x+8-(4/12x)=0


Domain of the equation: 12x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(+4/12x)+8=0

We get rid of parentheses

2x-4/12x+8=0

We multiply all the terms by the denominator


2x*12x+8*12x-4=0

Wy multiply elements

24x^2+96x-4=0

a = 24; b = 96; c = -4;
Δ = b2-4ac
Δ = 962-4·24·(-4)
Δ = 9600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9600}=\sqrt{1600*6}=\sqrt{1600}*\sqrt{6}=40\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-40\sqrt{6}}{2*24}=\frac{-96-40\sqrt{6}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+40\sqrt{6}}{2*24}=\frac{-96+40\sqrt{6}}{48}
$