2x+8=64/x

Solution for 2x+8=64/x equation:

2x+8=64/x

We move all terms to the left:

2x+8-(64/x)=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(+64/x)+8=0

We get rid of parentheses

2x-64/x+8=0

We multiply all the terms by the denominator


2x*x+8*x-64=0

We add all the numbers together, and all the variables

8x+2x*x-64=0

Wy multiply elements

2x^2+8x-64=0

a = 2; b = 8; c = -64;
Δ = b2-4ac
Δ = 82-4·2·(-64)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24}{2*2}=\frac{-32}{4}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24}{2*2}=\frac{16}{4}
=4
$