2x+9(x+1)=8(2x+)2-5

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Solution for 2x+9(x+1)=8(2x+)2-5 equation: 



2x+9(x+1)=8(2x+)2-5

We move all terms to the left:

2x+9(x+1)-(8(2x+)2-5)=0

We add all the numbers together, and all the variables

2x+9(x+1)-(8(+2x)2-5)=0

We multiply parentheses

2x+9x-(8(+2x)2-5)+9=0



We calculate terms in parentheses: -(8(+2x)2-5), so:

8(+2x)2-5

We multiply parentheses

32x-5

Back to the equation:

-(32x-5)



We add all the numbers together, and all the variables

11x-(32x-5)+9=0

We get rid of parentheses

11x-32x+5+9=0

We add all the numbers together, and all the variables

-21x+14=0

We move all terms containing x to the left, all other terms to the right

-21x=-14

x=-14/-21

x=2/3

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