2x+9(x+1)=8(2x+2)-5

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Solution for 2x+9(x+1)=8(2x+2)-5 equation: 



2x+9(x+1)=8(2x+2)-5

We move all terms to the left:

2x+9(x+1)-(8(2x+2)-5)=0

We multiply parentheses

2x+9x-(8(2x+2)-5)+9=0



We calculate terms in parentheses: -(8(2x+2)-5), so:

8(2x+2)-5

We multiply parentheses

16x+16-5

We add all the numbers together, and all the variables

16x+11

Back to the equation:

-(16x+11)



We add all the numbers together, and all the variables

11x-(16x+11)+9=0

We get rid of parentheses

11x-16x-11+9=0

We add all the numbers together, and all the variables

-5x-2=0

We move all terms containing x to the left, all other terms to the right

-5x=2

x=2/-5

x=-2/5

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