2x+9/x-3=7

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Solution for 2x+9/x-3=7 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+9/x-3 = 7 // - 7

2*x+9/x-7-3 = 0

2*x^1+9*x^-1-10*x^0 = 0

(2*x^2-10*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-10*x^1+9*x^0) = 0

x^1

2*x^2-10*x+9 = 0

2*x^2-10*x+9 = 0

DELTA = (-10)^2-(2*4*9)

DELTA = 28

DELTA > 0

x = (28^(1/2)+10)/(2*2) or x = (10-28^(1/2))/(2*2)

x = (2*7^(1/2)+10)/4 or x = (10-2*7^(1/2))/4

x in { (10-2*7^(1/2))/4, (2*7^(1/2)+10)/4} 

x in { (10-2*7^(1/2))/4, (2*7^(1/2)+10)/4 }

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