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2x+9=10-(x-5)
We move all terms to the left:
2x+9-(10-(x-5))=0
We calculate terms in parentheses: -(10-(x-5)), so:We get rid of parentheses
10-(x-5)
determiningTheFunctionDomain -(x-5)+10
We get rid of parentheses
-x+5+10
We add all the numbers together, and all the variables
-1x+15
Back to the equation:
-(-1x+15)
2x+1x-15+9=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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