2x+x(x+8)=x(x-8)+6

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Solution for 2x+x(x+8)=x(x-8)+6 equation: 



2x+x(x+8)=x(x-8)+6

We move all terms to the left:

2x+x(x+8)-(x(x-8)+6)=0

We multiply parentheses

x^2+2x+8x-(x(x-8)+6)=0



We calculate terms in parentheses: -(x(x-8)+6), so:

x(x-8)+6

We multiply parentheses

x^2-8x+6

Back to the equation:

-(x^2-8x+6)



We add all the numbers together, and all the variables

x^2+10x-(x^2-8x+6)=0

We get rid of parentheses

x^2-x^2+10x+8x-6=0

We add all the numbers together, and all the variables

18x-6=0

We move all terms containing x to the left, all other terms to the right

18x=6

x=6/18

x=1/3

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