2x+x+(3x-2)=40

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Solution for 2x+x+(3x-2)=40 equation: 



2x+x+(3x-2)=40

We move all terms to the left:

2x+x+(3x-2)-(40)=0

We add all the numbers together, and all the variables

3x+(3x-2)-40=0

We get rid of parentheses

3x+3x-2-40=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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