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2x+x+3/2x+45=180
We move all terms to the left:
2x+x+3/2x+45-(180)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3x+3/2x-135=0
We multiply all the terms by the denominator
3x*2x-135*2x+3=0
Wy multiply elements
6x^2-270x+3=0
a = 6; b = -270; c = +3;
Δ = b2-4ac
Δ = -2702-4·6·3
Δ = 72828
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72828}=\sqrt{10404*7}=\sqrt{10404}*\sqrt{7}=102\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-270)-102\sqrt{7}}{2*6}=\frac{270-102\sqrt{7}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-270)+102\sqrt{7}}{2*6}=\frac{270+102\sqrt{7}}{12} $
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