2x+x+3/7=2

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Solution for 2x+x+3/7=2 equation: 



2x+x+3/7=2

We move all terms to the left:

2x+x+3/7-(2)=0

determiningTheFunctionDomain
2x+x-2+3/7=0

We add all the numbers together, and all the variables

3x-2+3/7=0

We multiply all the terms by the denominator


3x*7+3-2*7=0

We add all the numbers together, and all the variables

3x*7-11=0

Wy multiply elements

21x-11=0

We move all terms containing x to the left, all other terms to the right

21x=11

x=11/21

x=11/21

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