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2x+x+6=3(x+1)-1
We move all terms to the left:
2x+x+6-(3(x+1)-1)=0
We add all the numbers together, and all the variables
3x-(3(x+1)-1)+6=0
We calculate terms in parentheses: -(3(x+1)-1), so:We get rid of parentheses
3(x+1)-1
We multiply parentheses
3x+3-1
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
3x-3x-2+6=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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