2x+x2+1=35

Solution for 2x+x2+1=35 equation:

2x+x2+1=35

We move all terms to the left:

2x+x2+1-(35)=0

We add all the numbers together, and all the variables

x^2+2x-34=0

a = 1; b = 2; c = -34;
Δ = b2-4ac
Δ = 22-4·1·(-34)
Δ = 140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{140}=\sqrt{4*35}=\sqrt{4}*\sqrt{35}=2\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{35}}{2*1}=\frac{-2-2\sqrt{35}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{35}}{2*1}=\frac{-2+2\sqrt{35}}{2}
$