2x+x=2x+(2x-3)+(x-1)=76

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Solution for 2x+x=2x+(2x-3)+(x-1)=76 equation: 



2x+x=2x+(2x-3)+(x-1)=76

We move all terms to the left:

2x+x-(2x+(2x-3)+(x-1))=0

We add all the numbers together, and all the variables

3x-(2x+(2x-3)+(x-1))=0



We calculate terms in parentheses: -(2x+(2x-3)+(x-1)), so:

2x+(2x-3)+(x-1)

We get rid of parentheses

2x+2x+x-3-1

We add all the numbers together, and all the variables

5x-4

Back to the equation:

-(5x-4)



We get rid of parentheses

3x-5x+4=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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