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2x+x=3(x-2)+7
We move all terms to the left:
2x+x-(3(x-2)+7)=0
We add all the numbers together, and all the variables
3x-(3(x-2)+7)=0
We calculate terms in parentheses: -(3(x-2)+7), so:We get rid of parentheses
3(x-2)+7
We multiply parentheses
3x-6+7
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
3x-3x-1=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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