2x-((6x+4))/7=5+9x

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Solution for 2x-((6x+4))/7=5+9x equation: 



2x-((6x+4))/7=5+9x

We move all terms to the left:

2x-((6x+4))/7-(5+9x)=0

We add all the numbers together, and all the variables

2x-((6x+4))/7-(9x+5)=0

We get rid of parentheses

2x-((6x+4))/7-9x-5=0

We multiply all the terms by the denominator


2x*7-((6x+4))-9x*7-5*7=0



We calculate terms in parentheses: -((6x+4)), so:

(6x+4)

We get rid of parentheses

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

2x*7-(6x+4)-9x*7-35=0

Wy multiply elements

14x-(6x+4)-63x-35=0

We get rid of parentheses

14x-6x-63x-4-35=0

We add all the numbers together, and all the variables

-55x-39=0

We move all terms containing x to the left, all other terms to the right

-55x=39

x=39/-55

x=-39/55

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