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2x-(1/4x)=-28
We move all terms to the left:
2x-(1/4x)-(-28)=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(+1/4x)-(-28)=0
We add all the numbers together, and all the variables
2x-(+1/4x)+28=0
We get rid of parentheses
2x-1/4x+28=0
We multiply all the terms by the denominator
2x*4x+28*4x-1=0
Wy multiply elements
8x^2+112x-1=0
a = 8; b = 112; c = -1;
Δ = b2-4ac
Δ = 1122-4·8·(-1)
Δ = 12576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12576}=\sqrt{16*786}=\sqrt{16}*\sqrt{786}=4\sqrt{786}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-4\sqrt{786}}{2*8}=\frac{-112-4\sqrt{786}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+4\sqrt{786}}{2*8}=\frac{-112+4\sqrt{786}}{16} $
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