2x-(2+4x)=3(x+2)+1

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Solution for 2x-(2+4x)=3(x+2)+1 equation: 



2x-(2+4x)=3(x+2)+1

We move all terms to the left:

2x-(2+4x)-(3(x+2)+1)=0

We add all the numbers together, and all the variables

2x-(4x+2)-(3(x+2)+1)=0

We get rid of parentheses

2x-4x-(3(x+2)+1)-2=0



We calculate terms in parentheses: -(3(x+2)+1), so:

3(x+2)+1

We multiply parentheses

3x+6+1

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

-2x-(3x+7)-2=0

We get rid of parentheses

-2x-3x-7-2=0

We add all the numbers together, and all the variables

-5x-9=0

We move all terms containing x to the left, all other terms to the right

-5x=9

x=9/-5

x=-1+4/5

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