2x-(3-4x)=6+(x-9)+5x

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Solution for 2x-(3-4x)=6+(x-9)+5x equation: 



2x-(3-4x)=6+(x-9)+5x

We move all terms to the left:

2x-(3-4x)-(6+(x-9)+5x)=0

We add all the numbers together, and all the variables

2x-(-4x+3)-(6+(x-9)+5x)=0

We get rid of parentheses

2x+4x-(6+(x-9)+5x)-3=0



We calculate terms in parentheses: -(6+(x-9)+5x), so:

6+(x-9)+5x

determiningTheFunctionDomain
(x-9)+5x+6

We add all the numbers together, and all the variables

5x+(x-9)+6

We get rid of parentheses

5x+x-9+6

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We add all the numbers together, and all the variables

6x-(6x-3)-3=0

We get rid of parentheses

6x-6x+3-3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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