2x-(3x+1)=62(x+1)+x=3x

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Solution for 2x-(3x+1)=62(x+1)+x=3x equation: 



2x-(3x+1)=62(x+1)+x=3x

We move all terms to the left:

2x-(3x+1)-(62(x+1)+x)=0

We get rid of parentheses

2x-3x-(62(x+1)+x)-1=0



We calculate terms in parentheses: -(62(x+1)+x), so:

62(x+1)+x

We add all the numbers together, and all the variables

x+62(x+1)

We multiply parentheses

x+62x+62

We add all the numbers together, and all the variables

63x+62

Back to the equation:

-(63x+62)



We add all the numbers together, and all the variables

-1x-(63x+62)-1=0

We get rid of parentheses

-1x-63x-62-1=0

We add all the numbers together, and all the variables

-64x-63=0

We move all terms containing x to the left, all other terms to the right

-64x=63

x=63/-64

x=-63/64

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