2x-(3x+2)=3(x+3)-3

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Solution for 2x-(3x+2)=3(x+3)-3 equation: 



2x-(3x+2)=3(x+3)-3

We move all terms to the left:

2x-(3x+2)-(3(x+3)-3)=0

We get rid of parentheses

2x-3x-(3(x+3)-3)-2=0



We calculate terms in parentheses: -(3(x+3)-3), so:

3(x+3)-3

We multiply parentheses

3x+9-3

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

-1x-(3x+6)-2=0

We get rid of parentheses

-1x-3x-6-2=0

We add all the numbers together, and all the variables

-4x-8=0

We move all terms containing x to the left, all other terms to the right

-4x=8

x=8/-4

x=-2

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