2x-(3x+4)=2(4x-5)+

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Solution for 2x-(3x+4)=2(4x-5)+ equation: 



2x-(3x+4)=2(4x-5)+

We move all terms to the left:

2x-(3x+4)-(2(4x-5)+)=0

We get rid of parentheses

2x-3x-(2(4x-5)+)-4=0



We calculate terms in parentheses: -(2(4x-5)+), so:

2(4x-5)+

We add all the numbers together, and all the variables

2(4x-5)

We multiply parentheses

8x-10

Back to the equation:

-(8x-10)



We add all the numbers together, and all the variables

-1x-(8x-10)-4=0

We get rid of parentheses

-1x-8x+10-4=0

We add all the numbers together, and all the variables

-9x+6=0

We move all terms containing x to the left, all other terms to the right

-9x=-6

x=-6/-9

x=2/3

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