2x-(3x-(9x+1)-8)=12x-(3x-(5-2x)-10+18x)

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Solution for 2x-(3x-(9x+1)-8)=12x-(3x-(5-2x)-10+18x) equation: 



2x-(3x-(9x+1)-8)=12x-(3x-(5-2x)-10+18x)

We move all terms to the left:

2x-(3x-(9x+1)-8)-(12x-(3x-(5-2x)-10+18x))=0

We add all the numbers together, and all the variables

2x-(3x-(9x+1)-8)-(12x-(3x-(-2x+5)-10+18x))=0



We calculate terms in parentheses: -(3x-(9x+1)-8), so:

3x-(9x+1)-8

We get rid of parentheses

3x-9x-1-8

We add all the numbers together, and all the variables

-6x-9

Back to the equation:

-(-6x-9)





We calculate terms in parentheses: -(12x-(3x-(-2x+5)-10+18x)), so:

12x-(3x-(-2x+5)-10+18x)



We calculate terms in parentheses: -(3x-(-2x+5)-10+18x), so:

3x-(-2x+5)-10+18x

determiningTheFunctionDomain
3x-(-2x+5)+18x-10

We add all the numbers together, and all the variables

21x-(-2x+5)-10

We get rid of parentheses

21x+2x-5-10

We add all the numbers together, and all the variables

23x-15

Back to the equation:

-(23x-15)



We get rid of parentheses

12x-23x+15

We add all the numbers together, and all the variables

-11x+15

Back to the equation:

-(-11x+15)



We get rid of parentheses

2x+6x+11x+9-15=0

We add all the numbers together, and all the variables

19x-6=0

We move all terms containing x to the left, all other terms to the right

19x=6

x=6/19

x=6/19

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