2x-(3x-2)=16

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Solution for 2x-(3x-2)=16 equation: 



2x-(3x-2)=16

We move all terms to the left:

2x-(3x-2)-(16)=0

We get rid of parentheses

2x-3x+2-16=0

We add all the numbers together, and all the variables

-1x-14=0

We move all terms containing x to the left, all other terms to the right

-x=14

x=14/-1

x=-14

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