2x-(3x-5)=4(3-2x)+(5x-2)

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Solution for 2x-(3x-5)=4(3-2x)+(5x-2) equation: 



2x-(3x-5)=4(3-2x)+(5x-2)

We move all terms to the left:

2x-(3x-5)-(4(3-2x)+(5x-2))=0

We add all the numbers together, and all the variables

2x-(3x-5)-(4(-2x+3)+(5x-2))=0

We get rid of parentheses

2x-3x-(4(-2x+3)+(5x-2))+5=0



We calculate terms in parentheses: -(4(-2x+3)+(5x-2)), so:

4(-2x+3)+(5x-2)

We multiply parentheses

-8x+(5x-2)+12

We get rid of parentheses

-8x+5x-2+12

We add all the numbers together, and all the variables

-3x+10

Back to the equation:

-(-3x+10)



We add all the numbers together, and all the variables

-1x-(-3x+10)+5=0

We get rid of parentheses

-1x+3x-10+5=0

We add all the numbers together, and all the variables

2x-5=0

We move all terms containing x to the left, all other terms to the right

2x=5

x=5/2

x=2+1/2

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