2x-(3y+4)=2x-3y+4

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Solution for 2x-(3y+4)=2x-3y+4 equation:


Simplifying
2x + -1(3y + 4) = 2x + -3y + 4

Reorder the terms:
2x + -1(4 + 3y) = 2x + -3y + 4
2x + (4 * -1 + 3y * -1) = 2x + -3y + 4
2x + (-4 + -3y) = 2x + -3y + 4

Reorder the terms:
-4 + 2x + -3y = 2x + -3y + 4

Reorder the terms:
-4 + 2x + -3y = 4 + 2x + -3y

Add '-2x' to each side of the equation.
-4 + 2x + -2x + -3y = 4 + 2x + -2x + -3y

Combine like terms: 2x + -2x = 0
-4 + 0 + -3y = 4 + 2x + -2x + -3y
-4 + -3y = 4 + 2x + -2x + -3y

Combine like terms: 2x + -2x = 0
-4 + -3y = 4 + 0 + -3y
-4 + -3y = 4 + -3y

Add '3y' to each side of the equation.
-4 + -3y + 3y = 4 + -3y + 3y

Combine like terms: -3y + 3y = 0
-4 + 0 = 4 + -3y + 3y
-4 = 4 + -3y + 3y

Combine like terms: -3y + 3y = 0
-4 = 4 + 0
-4 = 4

Solving
-4 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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