2x-(5x+2)=7+(3x-2)

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Solution for 2x-(5x+2)=7+(3x-2) equation: 



2x-(5x+2)=7+(3x-2)

We move all terms to the left:

2x-(5x+2)-(7+(3x-2))=0

We get rid of parentheses

2x-5x-(7+(3x-2))-2=0



We calculate terms in parentheses: -(7+(3x-2)), so:

7+(3x-2)

determiningTheFunctionDomain
(3x-2)+7

We get rid of parentheses

3x-2+7

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

-3x-(3x+5)-2=0

We get rid of parentheses

-3x-3x-5-2=0

We add all the numbers together, and all the variables

-6x-7=0

We move all terms containing x to the left, all other terms to the right

-6x=7

x=7/-6

x=-1+1/6

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