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2x-(5x+3)=6x-3(3x+6)+15
We move all terms to the left:
2x-(5x+3)-(6x-3(3x+6)+15)=0
We get rid of parentheses
2x-5x-(6x-3(3x+6)+15)-3=0
We calculate terms in parentheses: -(6x-3(3x+6)+15), so:We add all the numbers together, and all the variables
6x-3(3x+6)+15
We multiply parentheses
6x-9x-18+15
We add all the numbers together, and all the variables
-3x-3
Back to the equation:
-(-3x-3)
-3x-(-3x-3)-3=0
We get rid of parentheses
-3x+3x+3-3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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