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2x-(6+2)=3(x-5)+1
We move all terms to the left:
2x-(6+2)-(3(x-5)+1)=0
We add all the numbers together, and all the variables
2x-(3(x-5)+1)-8=0
We calculate terms in parentheses: -(3(x-5)+1), so:We get rid of parentheses
3(x-5)+1
We multiply parentheses
3x-15+1
We add all the numbers together, and all the variables
3x-14
Back to the equation:
-(3x-14)
2x-3x+14-8=0
We add all the numbers together, and all the variables
-1x+6=0
We move all terms containing x to the left, all other terms to the right
-x=-6
x=-6/-1
x=+6
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