2x-(6x+4)=(x00-9)-6(2x-4)

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Solution for 2x-(6x+4)=(x00-9)-6(2x-4) equation: 



2x-(6x+4)=(x00-9)-6(2x-4)

We move all terms to the left:

2x-(6x+4)-((x00-9)-6(2x-4))=0

We add all the numbers together, and all the variables

2x-(6x+4)-((x-9)-6(2x-4))=0

We get rid of parentheses

2x-6x-((x-9)-6(2x-4))-4=0



We calculate terms in parentheses: -((x-9)-6(2x-4)), so:

(x-9)-6(2x-4)

We multiply parentheses

(x-9)-12x+24

We get rid of parentheses

x-12x-9+24

We add all the numbers together, and all the variables

-11x+15

Back to the equation:

-(-11x+15)



We add all the numbers together, and all the variables

-4x-(-11x+15)-4=0

We get rid of parentheses

-4x+11x-15-4=0

We add all the numbers together, and all the variables

7x-19=0

We move all terms containing x to the left, all other terms to the right

7x=19

x=19/7

x=2+5/7

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