2x-(7+3x)=16-(3x+1)

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Solution for 2x-(7+3x)=16-(3x+1) equation:



2x-(7+3x)=16-(3x+1)
We move all terms to the left:
2x-(7+3x)-(16-(3x+1))=0
We add all the numbers together, and all the variables
2x-(3x+7)-(16-(3x+1))=0
We get rid of parentheses
2x-3x-(16-(3x+1))-7=0
We calculate terms in parentheses: -(16-(3x+1)), so:
16-(3x+1)
determiningTheFunctionDomain -(3x+1)+16
We get rid of parentheses
-3x-1+16
We add all the numbers together, and all the variables
-3x+15
Back to the equation:
-(-3x+15)
We add all the numbers together, and all the variables
-1x-(-3x+15)-7=0
We get rid of parentheses
-1x+3x-15-7=0
We add all the numbers together, and all the variables
2x-22=0
We move all terms containing x to the left, all other terms to the right
2x=22
x=22/2
x=11

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