2x-(8+3x)=12-5(x-2)

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Solution for 2x-(8+3x)=12-5(x-2) equation: 



2x-(8+3x)=12-5(x-2)

We move all terms to the left:

2x-(8+3x)-(12-5(x-2))=0

We add all the numbers together, and all the variables

2x-(3x+8)-(12-5(x-2))=0

We get rid of parentheses

2x-3x-(12-5(x-2))-8=0



We calculate terms in parentheses: -(12-5(x-2)), so:

12-5(x-2)

determiningTheFunctionDomain
-5(x-2)+12

We multiply parentheses

-5x+10+12

We add all the numbers together, and all the variables

-5x+22

Back to the equation:

-(-5x+22)



We add all the numbers together, and all the variables

-1x-(-5x+22)-8=0

We get rid of parentheses

-1x+5x-22-8=0

We add all the numbers together, and all the variables

4x-30=0

We move all terms containing x to the left, all other terms to the right

4x=30

x=30/4

x=7+1/2

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