2x-(x+4)=10-2(x-8)

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Solution for 2x-(x+4)=10-2(x-8) equation: 



2x-(x+4)=10-2(x-8)

We move all terms to the left:

2x-(x+4)-(10-2(x-8))=0

We get rid of parentheses

2x-x-(10-2(x-8))-4=0



We calculate terms in parentheses: -(10-2(x-8)), so:

10-2(x-8)

determiningTheFunctionDomain
-2(x-8)+10

We multiply parentheses

-2x+16+10

We add all the numbers together, and all the variables

-2x+26

Back to the equation:

-(-2x+26)



We add all the numbers together, and all the variables

x-(-2x+26)-4=0

We get rid of parentheses

x+2x-26-4=0

We add all the numbers together, and all the variables

3x-30=0

We move all terms containing x to the left, all other terms to the right

3x=30

x=30/3

x=10

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