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2x-(x-1)=3(x-2)+7
We move all terms to the left:
2x-(x-1)-(3(x-2)+7)=0
We get rid of parentheses
2x-x-(3(x-2)+7)+1=0
We calculate terms in parentheses: -(3(x-2)+7), so:We add all the numbers together, and all the variables
3(x-2)+7
We multiply parentheses
3x-6+7
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
x-(3x+1)+1=0
We get rid of parentheses
x-3x-1+1=0
We add all the numbers together, and all the variables
-2x=0
x=0/-2
x=0
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