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2x-(x-1)=3+3(x-2)
We move all terms to the left:
2x-(x-1)-(3+3(x-2))=0
We get rid of parentheses
2x-x-(3+3(x-2))+1=0
We calculate terms in parentheses: -(3+3(x-2)), so:We add all the numbers together, and all the variables
3+3(x-2)
determiningTheFunctionDomain 3(x-2)+3
We multiply parentheses
3x-6+3
We add all the numbers together, and all the variables
3x-3
Back to the equation:
-(3x-3)
x-(3x-3)+1=0
We get rid of parentheses
x-3x+3+1=0
We add all the numbers together, and all the variables
-2x+4=0
We move all terms containing x to the left, all other terms to the right
-2x=-4
x=-4/-2
x=+2
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