2x-(x-2)-2(10-x)=5(x-2)

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Solution for 2x-(x-2)-2(10-x)=5(x-2) equation: 



2x-(x-2)-2(10-x)=5(x-2)

We move all terms to the left:

2x-(x-2)-2(10-x)-(5(x-2))=0

We add all the numbers together, and all the variables

2x-(x-2)-2(-1x+10)-(5(x-2))=0

We multiply parentheses

2x-(x-2)+2x-(5(x-2))-20=0

We get rid of parentheses

2x-x+2x-(5(x-2))+2-20=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

3x-(5x-10)-18=0

We get rid of parentheses

3x-5x+10-18=0

We add all the numbers together, and all the variables

-2x-8=0

We move all terms containing x to the left, all other terms to the right

-2x=8

x=8/-2

x=-4

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