2x-0.5(x-8)=-4(x+2)+1

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Solution for 2x-0.5(x-8)=-4(x+2)+1 equation:



2x-0.5(x-8)=-4(x+2)+1
We move all terms to the left:
2x-0.5(x-8)-(-4(x+2)+1)=0
We multiply parentheses
2x-0.5x-(-4(x+2)+1)+4=0
We calculate terms in parentheses: -(-4(x+2)+1), so:
-4(x+2)+1
We multiply parentheses
-4x-8+1
We add all the numbers together, and all the variables
-4x-7
Back to the equation:
-(-4x-7)
We add all the numbers together, and all the variables
1.5x-(-4x-7)+4=0
We get rid of parentheses
1.5x+4x+7+4=0
We add all the numbers together, and all the variables
5.5x+11=0
We move all terms containing x to the left, all other terms to the right
5.5x=-11
x=-11/5.5
x=-2

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