2x-1-1=4x-12-2(-5+X)

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Solution for 2x-1-1=4x-12-2(-5+X) equation: 



2x-1-1=4x-12-2(-5+x)

We move all terms to the left:

2x-1-1-(4x-12-2(-5+x))=0

We add all the numbers together, and all the variables

2x-(4x-12-2(x-5))-1-1=0

We add all the numbers together, and all the variables

2x-(4x-12-2(x-5))-2=0



We calculate terms in parentheses: -(4x-12-2(x-5)), so:

4x-12-2(x-5)

determiningTheFunctionDomain
4x-2(x-5)-12

We multiply parentheses

4x-2x+10-12

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We get rid of parentheses

2x-2x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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