2x-1-1=x-3-3(-5+x)

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Solution for 2x-1-1=x-3-3(-5+x) equation: 



2x-1-1=x-3-3(-5+x)

We move all terms to the left:

2x-1-1-(x-3-3(-5+x))=0

We add all the numbers together, and all the variables

2x-(x-3-3(x-5))-1-1=0

We add all the numbers together, and all the variables

2x-(x-3-3(x-5))-2=0



We calculate terms in parentheses: -(x-3-3(x-5)), so:

x-3-3(x-5)

determiningTheFunctionDomain
x-3(x-5)-3

We multiply parentheses

x-3x+15-3

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We get rid of parentheses

2x+2x-12-2=0

We add all the numbers together, and all the variables

4x-14=0

We move all terms containing x to the left, all other terms to the right

4x=14

x=14/4

x=3+1/2

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