2x-1-3x/10+3/2=2(x-3)+1/5

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Solution for 2x-1-3x/10+3/2=2(x-3)+1/5 equation: 



2x-1-3x/10+3/2=2(x-3)+1/5

We move all terms to the left:

2x-1-3x/10+3/2-(2(x-3)+1/5)=0

We calculate fractions


(-30x^2)/()+2x+(-(2(x-3)+1*10*2)/()+()/()-1=0

We can not solve this equation

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