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2x-1/2x+5=x/5x-4
We move all terms to the left:
2x-1/2x+5-(x/5x-4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x-4)!=0We get rid of parentheses
x∈R
2x-1/2x-x/5x+4+5=0
We calculate fractions
(-2x^2)/10x^2+2x+(-5x)/10x^2+4+5=0
We add all the numbers together, and all the variables
(-2x^2)/10x^2+2x+(-5x)/10x^2+9=0
We multiply all the terms by the denominator
(-2x^2)+2x*10x^2+(-5x)+9*10x^2=0
Wy multiply elements
(-2x^2)+20x^3+90x^2+(-5x)=0
We get rid of parentheses
-2x^2+20x^3+90x^2-5x=0
We do not support expression: x^3
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