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2x-1/3(9x-3)=-(5x+1)-2x
We move all terms to the left:
2x-1/3(9x-3)-(-(5x+1)-2x)=0
Domain of the equation: 3(9x-3)!=0We multiply all the terms by the denominator
x∈R
2x*3(9x-3)-((-(5x+1)-2x))*3(9x-3)-1=0
We calculate terms in parentheses: -((-(5x+1)-2x))*3(9x-3), so:Wy multiply elements
(-(5x+1)-2x))*3(9x-3
6x^2(9-((-(5x+1)-2x))*3(9x-3)-1=0
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