2x-1/3x+1=6x-1/9x-3

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Solution for 2x-1/3x+1=6x-1/9x-3 equation: 



2x-1/3x+1=6x-1/9x-3

We move all terms to the left:

2x-1/3x+1-(6x-1/9x-3)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 9x-3)!=0

x∈R



We get rid of parentheses

2x-1/3x-6x+1/9x+3+1=0

We calculate fractions


2x-6x+(-9x)/27x^2+3x/27x^2+3+1=0

We add all the numbers together, and all the variables

-4x+(-9x)/27x^2+3x/27x^2+4=0

We multiply all the terms by the denominator


-4x*27x^2+(-9x)+3x+4*27x^2=0

We add all the numbers together, and all the variables

3x-4x*27x^2+(-9x)+4*27x^2=0

Wy multiply elements

-108x^3+108x^2+3x+(-9x)=0

We get rid of parentheses

-108x^3+108x^2+3x-9x=0

We do not support expression: x^3

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