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2x-1/5+2=x/2-x
We move all terms to the left:
2x-1/5+2-(x/2-x)=0
Domain of the equation: 2-x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x)!=-2
x!=-2/1
x!=-2
x∈R
2x-(-1x+x/2)+2-1/5=0
We get rid of parentheses
2x+1x-x/2+2-1/5=0
We calculate fractions
There is no solution for this equation
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