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2x-1/9x=-28
We move all terms to the left:
2x-1/9x-(-28)=0
Domain of the equation: 9x!=0We add all the numbers together, and all the variables
x!=0/9
x!=0
x∈R
2x-1/9x+28=0
We multiply all the terms by the denominator
2x*9x+28*9x-1=0
Wy multiply elements
18x^2+252x-1=0
a = 18; b = 252; c = -1;
Δ = b2-4ac
Δ = 2522-4·18·(-1)
Δ = 63576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{63576}=\sqrt{36*1766}=\sqrt{36}*\sqrt{1766}=6\sqrt{1766}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(252)-6\sqrt{1766}}{2*18}=\frac{-252-6\sqrt{1766}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(252)+6\sqrt{1766}}{2*18}=\frac{-252+6\sqrt{1766}}{36} $
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