2x-10+3(2x-10)-2(x-5)=7(x+5)-2x-15

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Solution for 2x-10+3(2x-10)-2(x-5)=7(x+5)-2x-15 equation: 



2x-10+3(2x-10)-2(x-5)=7(x+5)-2x-15

We move all terms to the left:

2x-10+3(2x-10)-2(x-5)-(7(x+5)-2x-15)=0

We multiply parentheses

2x+6x-2x-(7(x+5)-2x-15)-30+10-10=0



We calculate terms in parentheses: -(7(x+5)-2x-15), so:

7(x+5)-2x-15

We add all the numbers together, and all the variables

-2x+7(x+5)-15

We multiply parentheses

-2x+7x+35-15

We add all the numbers together, and all the variables

5x+20

Back to the equation:

-(5x+20)



We add all the numbers together, and all the variables

6x-(5x+20)-30=0

We get rid of parentheses

6x-5x-20-30=0

We add all the numbers together, and all the variables

x-50=0

We move all terms containing x to the left, all other terms to the right

x=50

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