2x-10-2/6(9x-6)=25

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Solution for 2x-10-2/6(9x-6)=25 equation: 



2x-10-2/6(9x-6)=25

We move all terms to the left:

2x-10-2/6(9x-6)-(25)=0



Domain of the equation: 6(9x-6)!=0

x∈R



We add all the numbers together, and all the variables

2x-2/6(9x-6)-35=0

We multiply all the terms by the denominator


2x*6(9x-6)-35*6(9x-6)-2=0

Wy multiply elements

12x^2(9-210x(9-2=0

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