If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x-10=4x-2(5x-2)4x+3
We move all terms to the left:
2x-10-(4x-2(5x-2)4x+3)=0
We calculate terms in parentheses: -(4x-2(5x-2)4x+3), so:We get rid of parentheses
4x-2(5x-2)4x+3
We multiply parentheses
-40x^2+4x+16x+3
We add all the numbers together, and all the variables
-40x^2+20x+3
Back to the equation:
-(-40x^2+20x+3)
40x^2-20x+2x-3-10=0
We add all the numbers together, and all the variables
40x^2-18x-13=0
a = 40; b = -18; c = -13;
Δ = b2-4ac
Δ = -182-4·40·(-13)
Δ = 2404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2404}=\sqrt{4*601}=\sqrt{4}*\sqrt{601}=2\sqrt{601}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{601}}{2*40}=\frac{18-2\sqrt{601}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{601}}{2*40}=\frac{18+2\sqrt{601}}{80} $
| 2^x-6=2x+15 | | 6t+1/3=t+8/6+t-6/6 | | f+14=18 | | 4x-3=3(2x+1) | | 5x+-3=5x+5 | | (6t+1)/3=(t+8)/6+(t-6)/6 | | (6t+1)/3=(t-8)/6+(t-6)/6 | | 25x^2-10x+17=0 | | 5-6+n=13 | | -23=2y-3 | | -12=3-2k-38 | | -3.2x=41.28 | | (1/2)^x+2=12 | | (x•x)-7x+12x=(x-4)(x+3) | | -0.4x=36 | | -7(u+1)=25 | | 50=4x+80 | | a-15a=850 | | X•x-7x+12=(x-4)(x+3) | | 18=400*x*9/12 | | 2x-8-5x=16 | | 10w-35=85 | | 10w+5=85 | | -2x+3=-5x-3 | | 7-2=6x-1 | | -1/4x+2=-3x-9 | | 42y=84 | | 3x^-2-14x^-1-5x=0 | | (2x-4)=(7x+14) | | x-19.7=-14.48 | | 3=4+x/12 | | 7-5x=-15 |