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2x-11/5x+11=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
2x*5x+11*5x-11=0
Wy multiply elements
10x^2+55x-11=0
a = 10; b = 55; c = -11;
Δ = b2-4ac
Δ = 552-4·10·(-11)
Δ = 3465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3465}=\sqrt{9*385}=\sqrt{9}*\sqrt{385}=3\sqrt{385}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-3\sqrt{385}}{2*10}=\frac{-55-3\sqrt{385}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+3\sqrt{385}}{2*10}=\frac{-55+3\sqrt{385}}{20} $
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