2x-12/x-8/8x-48/3x-24

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Solution for 2x-12/x-8/8x-48/3x-24 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-((8/8)*x)-((48/3)*x)-(12/x)-24 = 0

2*x-x-16*x-12*x^-1-24 = 0

-15*x^1-12*x^-1-24*x^0 = 0

(-15*x^2-24*x^1-12*x^0)/(x^1) = 0 // * x^2

x^1*(-15*x^2-24*x^1-12*x^0) = 0

x^1

-15*x^2-24*x-12 = 0

-15*x^2-24*x-12 = 0

DELTA = (-24)^2-(-15*(-12)*4)

DELTA = -144

DELTA < 0

x in { } 

x belongs to the empty set

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