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2x-12=6-(3x-2)
We move all terms to the left:
2x-12-(6-(3x-2))=0
We calculate terms in parentheses: -(6-(3x-2)), so:We get rid of parentheses
6-(3x-2)
determiningTheFunctionDomain -(3x-2)+6
We get rid of parentheses
-3x+2+6
We add all the numbers together, and all the variables
-3x+8
Back to the equation:
-(-3x+8)
2x+3x-8-12=0
We add all the numbers together, and all the variables
5x-20=0
We move all terms containing x to the left, all other terms to the right
5x=20
x=20/5
x=4
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